Topic: Metrology and Inspection
A linear measuring scale has a known systematic error of + 0.05 mm for every 100 mm of measurement. If this scale is used to measure a distance and the reading obtained is 5 meters, what is the actual length of the distance?
- A. 4995.00 mm
- B. 5002.50 mm
- C. 5000.00 mm
- D. 4997.50 mm
Answer: D. 4997.50 mm
Explanation: Measured reading = $5~m = 5000~mm$.
The scale has an error of $+0.05~mm$ per $100~mm$ measured. This means the scale overestimates the length.
Total Error = $\left(\frac{5000}{100}\right) \times 0.05 = 50 \times 0.05 = 2.50~mm$.
Actual Length = Measured Reading - Total Error = $5000 - 2.50 = 4997.50~mm$.