Topic: Industrial Engineering
For a PERT activity, the optimistic time is 6 minutes, the most likely time is 9 minutes and pessimistic time is 16 minutes. The expected time of the activity (in seconds) is
- A. 600
- B. 540
- C. 620
- D. 580
Answer: D. 580
Explanation: Expected time $T_e = (t_o + 4t_m + t_p) / 6 = (6 + 4(9) + 16) / 6 = (6 + 36 + 16) / 6 = 58 / 6$ minutes. Converting to seconds: $(58 / 6) * 60 = 58 * 10 = 580$ seconds.