Topic: Manufacturing
A 20 mm diameter Aluminium rod is turned to 19 mm diameter in a single pass. If the axial speed of the tool is 200 mm/min and the spindle rotate at 600 rpm, the material removal rate is nearly
- A. 6100 mm³/min
- B. 12250 mm³/min
- C. 3050 mm³/min
- D. 9150 mm³/min
Answer: A. 6100 mm³/min
Explanation: Material Removal Rate (MRR) for turning = (pi/4) * (D_initial^2 - D_final^2) * feed_velocity. MRR = (pi/4) * (20^2 - 19^2) * 200 = 50 * pi * (400 - 361) = 1950 * pi = 6126.1 mm³/min, which is nearly 6100 mm³/min.