In a screw jack of lead angle alpha, the effort required to lift the load W is given by (phi = Friction Angle)
- A. P = W tan(alpha - phi)
- B. P = W tan(alpha + phi)
- C. P = W cos(alpha - phi)
- D. P = W cos(alpha + phi)
Answer: B. P = W tan(alpha + phi)
ISRO Mechanical & Aerospace 2020 - Question 42
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