For a surface, the direct and diffuse components of the solar radiation are 400 and 300 W/m² and the direct radiation makes 60 deg angle with the normal. If the surface temperature is 300 K and effective sky temperature is 200 K, calculate net rate of radiation heat transfer. (Assume solar absorptivity and emissivity as 0.1 each; For calculation take Stefan Boltzmanns constant as 6 x 10^-8 W/m².K^4)
- A. 11 W/m²
- B. 45 W/m²
- C. 33 W/m²
- D. 64 W/m²
Answer: A. 11 W/m²