Topic: Metrology and Inspection
A hole is specified as 50(+0.050/-0.000) mm. The mating shaft has a clearance fit with minimum clearance of 0.02 mm. The tolerance on the shaft is 0.03 mm. Maximum clearance between hole and shaft is
- A. 0.100 mm
- B. 0.030 mm
- C. 0.080 mm
- D. 0.070 mm
Answer: A. 0.100 mm
Explanation: The maximum hole size is $50 + 0.050 = 50.050$ mm and the minimum hole size is $50.000$ mm. For a clearance fit, the minimum clearance is given by (Minimum hole size - Maximum shaft size) $= 0.02$ mm. Thus, Maximum shaft size $= 50.000 - 0.02 = 49.980$ mm. Since the shaft tolerance is $0.03$ mm, the Minimum shaft size $= 49.980 - 0.03 = 49.950$ mm. The maximum clearance is (Maximum hole size - Minimum shaft size) $= 50.050 - 49.950 = 0.100$ mm.