lim x->0 (x² + x - sinx) / x²
- A. 0
- B. infinity
- C. 1
- D. None of these
Answer: C. 1
Explanation: Using L'Hopital: (2x + 1 - cosx) / 2x. Apply again: (2 + sinx)/2 -> 2/2 = 1.
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lim x->0 (x² + x - sinx) / x²
Answer: C. 1
Explanation: Using L'Hopital: (2x + 1 - cosx) / 2x. Apply again: (2 + sinx)/2 -> 2/2 = 1.
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