A Carnot engine rejects 30% of absorbed heat to a sink at 30°C. The temperature of the heat source is
- A. 100°C
- B. 433°C
- C. 737°C
- D. 1010°C
Answer: C. 737°C
Explanation: Q_out = 0.3 Q_in. Q_out/Q_in = T_L/T_H = 0.3. T_L = 30+273 = 303 K. T_H = 303/0.3 = 1010 K. T_H = 1010 - 273 = 737 C.