Efficiency of Carnot engine is given as 80%. If the cycle direction is reversed, what will be the value of COP of reversed Carnot cycle
- A. 1.25
- B. 0.5
- C. 0.25
- D. none of the above
Answer: C. 0.25
Explanation: Efficiency n = (Th-Tl)/Th = 0.8. Tl/Th = 0.2. COP of Refrigerator = Tl / (Th-Tl) = (Tl/Th) / (1 - Tl/Th) = 0.2 / 0.8 = 0.25.