ISRO Mechanical & Aerospace 2012 - Question 6

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The number of degrees of freedom for a mechanism with 6 links and 7 binary joints is

Figure for question 6, ISRO Mechanical & Aerospace 2012

  • A. 0
  • B. 1
  • C. 2
  • D. 4

Answer: B. 1

Explanation: F = 3(N-1) - 2J. F = 3(6-1) - 2(7) = 15 - 14 = 1.

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