ISRO Mechanical & Aerospace 2012 - Question 1

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Area moment of inertia for the quadrant shown is

Figure for question 1, ISRO Mechanical & Aerospace 2012

  • A. \pi r^4 / 2
  • B. \pi r^4 / 4
  • C. \pi r^4 / 8
  • D. \pi r^4 / 16

Answer: D. \pi r^4 / 16

Explanation: For a full circle, I = \pi r^4 / 4. A quadrant is 1/4th. With respect to diametric axes, I = 1/4 * (\pi r^4 / 4) = \pi r^4 / 16.

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