Dimension of the hole is $50^{+0.02}_{-0.00}$ and shaft is $50^{+0.02}_{+0.00}$ mm. The minimum clearance is
- A. 0.02mm
- B. 0.00mm
- C. -0.02mm
- D. 0.01mm
Answer: C. -0.02mm
Explanation: Min Hole = 50.00. Max Shaft = 50.02. Min Clearance = 50.00 - 50.02 = -0.02 mm (Interference).