The rake angle of a cutting tool is 15°, shear angle 45° and cutting velocity 35 m/min. What is the velocity of chip along the tool face?
- A. 25.3 m/min
- B. 27.3 m/min
- C. 28.5 m/min
- D. 23.5 m/min
Answer: C. 28.5 m/min
Explanation: $V_c = V \frac{\sin \phi}{\cos(\phi-\alpha)} = 35 \frac{\sin 45}{\cos 30} \approx 28.5$.