A bar of 20 mm dia is tested in tension. It is observed that when a load of 38 kN is applied the extension measured over a gauge length of 200 mm is 0.12 mm and contraction in diameter is 0.0036 mm. Find the Poisson's ratio
- A. 0.2
- B. 0.3
- C. 0.25
- D. 0.33
Answer: B. 0.3
Explanation: $\mu = \frac{\epsilon_{lat}}{\epsilon_{long}} = \frac{0.0036/20}{0.12/200} = 0.3$.