Topic: Strength of Materials
With a punch for which the maximum crushing stress is 4 times the maximum shearing stress of the plate, the biggest hole that can be punched in the plate would be of diameter equal to
- A. 1/4 * Thickness of plate
- B. 1/2 * Thickness of plate
- C. Plate thickness
- D. 2 * plate thickness
Answer: C. Plate thickness
Explanation: Crushing stress = 4 * shearing stress. F / ((pi/4) * D²) = 4 * F / (pi * D * t). This simplifies to 4/D = 4/t, which means D = t (Diameter equals Plate thickness).