Topic: Fluid Mechanics
The transition Reynolds number for flow over a flat plate is 5x10^5. What is the distance from the leading edge at which transition will occur for flow of water with a uniform velocity of 1 m/s? (For water, the kinematic viscosity, v = 0.858x10^-6 m²/s)
- A. 1m
- B. 0.43m
- C. 43m
- D. 103m
Answer: B. 0.43m
Explanation: Re = (V * D) / v. Therefore, 5*10^5 = (1 * D) / (0.858*10^-6). D = 5*10^5 * 0.858*10^-6 = 0.429 m, which is approx 0.43 m.