Topic: Fluid Mechanics
Pipe 1, branches to three pipes as shown in the given figure. The areas and corresponding velocities are: Pipe 1 (V=50, A=20), Pipe 2 (V=V2, A=10), Pipe 3 (V=30, A=15), Pipe 4 (V=20, A=10). The value of V2 in cm per second will be

- A. 15
- B. 20
- C. 30
- D. 35
Answer: D. 35
Explanation: Using continuity equation: Q1 = Q2 + Q3 + Q4 => A1*V1 = A2*V2 + A3*V3 + A4*V4. 50*20 = V2*10 + 30*15 + 20*10. 1000 = 10*V2 + 450 + 200. 10*V2 = 350. V2 = 35 cm/sec.