Topic: Theory of Machines and Vibrations
Periodic time of simple pendulum is given by
- A. $2\pi\sqrt{\frac{l}{g}}$
- B. $2\pi\sqrt{\frac{g}{l}}$
- C. $\frac{1}{2\pi}\sqrt{\frac{l}{g}}$
- D. $\frac{1}{2\pi}\sqrt{\frac{g}{l}}$
Answer: A. $2\pi\sqrt{\frac{l}{g}}$
Explanation: A simple pendulum executes periodic motion. The time period (T) of a simple pendulum is given by $T = \frac{2\pi}{\omega} = 2\pi\sqrt{\frac{l}{g}}$, where l is the length of the string and g is acceleration due to gravity.