ISRO Mechanical & Aerospace 2006 - Question 36

All ISRO Mechanical & Aerospace papers | ISRO Mechanical & Aerospace 2006

Topic: Theory of Machines / Vibrations

The acceleration of Simple Harmonic Motion of a pendulum is proportional to

  • A. Length of pendulum
  • B. Time period
  • C. Angular velocity
  • D. Displacement

Answer: D. Displacement

Explanation: Equation for simple harmonic motion $x = A \sin \omega t$. Velocity $V = \frac{dx}{dt} = A \omega \cos \omega t$. Acceleration $a = \frac{dv}{dt} = -A \omega^{2} \sin \omega t = -\omega^{2}x$. Thus, acceleration is proportional to displacement ($a \propto x$).

| | All questions of ISRO Mechanical & Aerospace 2006