Section: Engineering Mathematics | Type: NAT | Marks: 2
Let π’(π₯, π‘) be the solution of the initial boundary value problem ππ’ ππ‘βπ2π’ ππ₯2 βπ’= 0, 0 < π₯< π, π‘> 0, π’(π₯, 0) = 2 sin (3π₯ 2 ) cos (π₯ 2) , 0 < π₯< π, π’(0, π‘) = π’(π, π‘) = 0, π‘> 0. Then the value of lim π‘ββπ’( 3π 4 , π‘) is equal to (rounded off to two decimal places)___________
Answer: 0.68 to 0.73