Section: Engineering Mathematics | Marks: 1
Let $u(x,t)$ be the solution of the initial value problem $\frac{\partial^2 u}{\partial t^2} = 9\frac{\partial^2 u}{\partial x^2}$, $t > 0$, $-\infty < x < \infty$, $u(x,0) = x + 5$, $\frac{\partial u}{\partial t}(x,0) = 0$. Then $u(2,2)$ is
- A. 7
- B. 13
- C. 14
- D. 26