Topic: Electromagnetics / Waveguides
The wave impedance for TE modes in a rectangular waveguide is
- A. $Z_{TE}=\frac{\eta E}{H}$
- B. $Z_{TE}=\frac{\eta}{\sqrt{1-(\frac{f_c}{f})^2}}$
- C. $Z_{TE}=\eta.\sqrt{1-(\frac{f_c}{f})^2}$
- D. Constant
Answer: B. $Z_{TE}=\frac{\eta}{\sqrt{1-(\frac{f_c}{f})^2}}$
Explanation: The wave impedance for Transverse Electric (TE) modes in a waveguide is given by $Z_{TE} = \frac{\eta}{\sqrt{1-(f_c/f)^2}}$, where $\eta$ is the intrinsic impedance of the dielectric medium, $f_c$ is the cutoff frequency, and $f$ is the operating frequency. (Note: For TM modes, it is $Z_{TM} = \eta \sqrt{1-(f_c/f)^2}$).