Topic: Calculus
$d(x-\frac{x^{3}}{3!}+\frac{x^{5}}{5!}-\frac{x^{7}}{7!}...)/dx$ is equal to:
- A. $sin(x)$
- B. $e^{x}$
- C. $cos(x)$
- D. $tan(x)$
Answer: C. $cos(x)$
Explanation: The series expression $(x-\frac{x^{3}}{3!}+\frac{x^{5}}{5!}-\frac{x^{7}}{7!}...)$ is the Taylor series expansion for $\sin(x)$. The derivative of $\sin(x)$ with respect to $x$ is $\cos(x)$.