Topic: Control Systems
Transfer function $H(s)=1/(s+3)^{2}$ has poles
- A. -3,3
- B. -3
- C. -3,-3
- D. 3
Answer: C. -3,-3
Explanation: The poles of a transfer function are found by equating the denominator polynomial to zero. For $H(s) = \frac{1}{(s+3)^2}$, the denominator is $(s+3)^2 = 0$. Solving this yields roots at $s = -3$ and $s = -3$. Thus, it has repeated poles at -3.