ISRO Electronics & Communication (ECE) 2012 - Question 41

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Topic: Electromagnetics

The S matrix of a lossless line having length $\lambda/4$ is

  • A. $\begin{bmatrix}1&0\\ 0&1\end{bmatrix}$
  • B. $\begin{bmatrix}1&-1\\ -1&1\end{bmatrix}$
  • C. $\begin{bmatrix}0&j\\ j&0\end{bmatrix}$
  • D. None of above

Answer: D. None of above

Explanation: $S=\begin{bmatrix}0&e^{-j\beta l}\\ e^{-j\beta l}&0\end{bmatrix}$. $l=\frac{\lambda}{4}$. $\beta l=\frac{2\pi}{\lambda}\times\frac{\lambda}{4}=\frac{\pi}{2}$. $e^{-j\beta l}=e^{-j\frac{\pi}{2}}=-j$. $S=\begin{bmatrix}0&-j\\ -j&0\end{bmatrix}$.

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