Topic: Electromagnetics
A signal source with 100 m wavelength is connected to the input terminals of a 150 m long transmission line terminated in its characteristic impedance. The phase difference between the voltages at two ends of the transmission line in steady-state condition is
- A. $2\pi$
- B. $3\pi$
- C. $4\pi$
- D. $\pi$
Answer: B. $3\pi$
Explanation: The phase difference is $\phi = \beta d = \frac{2\pi}{\lambda} \times d$.
Given $\lambda = 100\text{ m}$ and $d = 150\text{ m}$.
$\phi = \frac{2\pi}{100} \times 150 = 3\pi$.