Topic: Communication Systems
A signal $m_{1}(t)$ is band limited to 3.6 kHz and the three other signals $m_{2}(t)$, $m_{3}(t)$ and $m_{4}(t)$ are band limited to 1.2 kHz each, and these signals are transmitted by means of TDM. Then, what will be the transmission bandwidth of the channel?
- A. 7.2 kHz
- B. 14.4 kHz
- C. 3.6 kHz
- D. 2.4 kHz
Answer: A. 7.2 kHz
Explanation: $B.W.=R_{b}/2 = \frac{(3.6+1.2\times3)\times2}{2}=7.2~kHz$.