Topic: Communication Systems
Four voice signals each limited to 4 kHz and sampled at Nyquist rate, are converted into binary PCM signal using 256 quantization levels. The bit transmission rate for the time division multiplexing signal will be
- A. 8 kbps
- B. 64 kbps
- C. 256 kbps
- D. 5126 kbps
Answer: C. 256 kbps
Explanation: $Rate=n\cdot N\cdot f_{s}$. Here $n=4$ signals. $N = \log_{2}(256) = 8$ bits. $f_{s} = 2 \times 4 \text{ kHz} = 8 \text{ kHz}$. $Rate = 4 \times 8 \times 8 \text{ kbps} = 256 \text{ kbps}$.