Topic: Electronics Engineering
Assume the intrinsic stand off ratio for the UJT is 0.8 for the relaxation oscillator circuit given below. The frequency of oscillation of the circuit is approximately equal to
- A. 1.43 kHz
- B. 620 Hz
- C. 7 kHz
- D. 1.6 kHz
Answer: B. 620 Hz
Explanation: Frequency of oscillation of relaxation oscillator is $f_{o} = \frac{1}{RC~ln(\frac{1}{1-\eta})}$ Where, $\eta = $ intrinsic stand off ratio. $f_{o} = \frac{1}{10\times10^{3}\times0.1\times10^{-6}\times ln(\frac{1}{1-0.8})} = 621.3~Hz$.