Topic: Electronic Devices
If $\alpha=0.995$, $I_{E}=10$ mA and $I_{CO}=0.5~\mu A$ then $I_{CEO}$ will be
- A. $100~\mu A$
- B. 10.1 mA
- C. $25~\mu A$
- D. 10.5 mA
Answer: A. $100~\mu A$
Explanation: $I_{CEO}=\frac{I_{CO}}{1-\alpha}=\frac{0.5}{1-0.995}\mu A=100~\mu A.$