ISRO Electronics & Communication (ECE) 2007 - Question 77

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What will be dB gain for an increase of power level from 13 to 26 W

  • A. 1
  • B. 2
  • C. 8
  • D. 3

Answer: D. 3

Explanation: $Gain_{dB} = 10 \log_{10}(\frac{P_{out}}{P_{in}}) = 10 \log_{10}(\frac{26}{13}) = 10 \log_{10}(2) \approx 3$ dB.

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