A bag contains eight white and six red marbles. The probability of drawing two marbles of same colour is
- A. $\frac{8c_2 \cdot 6c_2}{14c_2}$
- B. $\frac{8c_2}{14c_2}+\frac{6c_2}{14c_2}$
- C. $\frac{8c_2 \cdot 6c_2}{14c_2 \cdot 14c_2}$
- D. $\frac{8c_2}{14c_2}+\frac{6c_2}{12c_2}$
Answer: B. $\frac{8c_2}{14c_2}+\frac{6c_2}{14c_2}$
Explanation: The probability of drawing two white marbles is $\frac{8c_2}{14c_2}$. The probability of drawing two red marbles is $\frac{6c_2}{14c_2}$. They are mutually exclusive, so Total probability = $\frac{8c_2}{14c_2} + \frac{6c_2}{14c_2}$.