If the PRF is 1200 and the pulse width is 1.5 $\mu$s, the duty cycle will be
- A. 12.5 percent
- B. 8 percent
- C. 0.18 percent
- D. 0.12 percent
Answer: C. 0.18 percent
Explanation: Pulse Repetition Time $T = \frac{1}{PRF} = \frac{1}{1200} = 8.33\times 10^{-4}$ s.\nDuty cycle $= \frac{\text{Pulse Width}}{T}\times 100 = \frac{1.5\times 10^{-6}}{8.33\times 10^{-4}}\times 100 = 0.18\%$.