In the ideal Op-amp circuit shown, $V_0$ is \n\n[Figure needs to be uploaded later]
- A. $2 V_s$
- B. $-2 V_s$
- C. $3 V_s$
- D. $-3 V_s$
Answer: C. $3 V_s$
Explanation: [Figure needs to be uploaded later]\n$V_0 = (1 + \frac{R_f}{R_1})V_s = (1 + \frac{2R}{R})V_s = 3V_s$