For the identity $AB+\overline{A}C+BC=AB+\overline{A}C$, the dual form is
- A. $(A+B)(\overline{A}+B)(B+C)=(A+B)(\overline{A}+C)$
- B. $(\overline{A}+\overline{B})(A+\overline{C})(\overline{B}+\overline{C})=(\overline{A}+\overline{B})(A+\overline{C})$
- C. $(A+B)(\overline{A}+C)(B+C)=(\overline{A}+\overline{B})(A+\overline{C})$
- D. $\overline{A}\overline{B}+A\overline{C}+\overline{B}\overline{C}=\overline{A}\overline{B}+A\overline{C}$
Answer: B. $(\overline{A}+\overline{B})(A+\overline{C})(\overline{B}+\overline{C})=(\overline{A}+\overline{B})(A+\overline{C})$
Explanation: For duality: Step: change AND to OR and vice-versa. Step: complemented to uncomplent and vice-versa. $(\overline{A}+\overline{B})(A+\overline{C})(\overline{B}+\overline{C})=(\overline{A}+\overline{B})(A+\overline{C})$.