A dc voltage V is applied to a series RL circuit. The steady state current is
- A. V/R
- B. V/L
- C. $\frac{V}{\sqrt{R²+L²}}$
- D. zero
Answer: A. V/R
Explanation: The transient current is given by $i(t) = \frac{V}{R}(1 - e^{-tR/L})$. At steady state ($t \rightarrow \infty$), $i(\infty) = \frac{V}{R}(1 - e^{-\infty}) = \frac{V}{R}$