ISRO Electrical Engineering (EE) 2023 - Question 14

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Find i in the following figure. [Figure description: A 6 A current source (arrow pointing left) across the top. A 2 Ω resistor in the top branch carrying current i (to the right). Below it, a 3 Ω resistor and a 2 Ω resistor in series along a middle horizontal wire with a 18 V battery (+ on top) connected from their junction to the bottom rail. The left vertical side has a 3 Ω resistor and the right vertical side a 1 Ω resistor, both connecting down to the bottom rail.]

  • A. 56/25 A
  • B. 96/25 A
  • C. 91/15 A
  • D. 81/16 A

Answer: B. 96/25 A

Explanation: Node equations (VL, VR with 18 V node): 7VL − 3VR = 72 and 4VR − VL = 6 give VR = 4.56 V, VL = 12.24 V; i = (VL − VR)/2 = 96/25 A.

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