If the impedance of an AC circuit is 10∠60° Ω then resistance in the circuit is
- A. 5 Ω
- B. 10 Ω
- C. 8.66 Ω
- D. 15 Ω
Answer: A. 5 Ω
Explanation: Impedance Z = 10 ∠60° Ω = 10 cos 60° + j 10 sin 60° = 10(0.5) + j 10(√3/2) = 5 + j 8.66 Ω. Thus, the real resistance is R = 5 Ω.