For the function f(t) = e^(-t/τ), the Taylor series approximation for t << τ is
- A. 1 + t/τ
- B. 1 - t/2τ^2
- C. 1 - t/τ
- D. 1 + t
Answer: C. 1 - t/τ
Explanation: The Maclaurin/Taylor expansion for e^x = 1 + x + x²/2! + … For x = −t/τ with t << τ, retaining first-order terms gives f(t) ≈ 1 − t/τ.