If tan θ = 8 / 15 and θ is acute, then cosec θ
- A. 8 / 17
- B. 8 / 15
- C. 17 / 8
- D. 17 / 15
Answer: C. 17 / 8
Explanation: In a right triangle with acute angle θ, tan θ = 8/15 (opposite = 8, adjacent = 15). Hypotenuse = √(8² + 15²) = √289 = 17. Therefore cosec θ = hypotenuse / opposite = 17/8.