ISRO Electrical Engineering (EE) 2013 - Question 80

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The unique polynomial P(x) of degree 2 such that: P(1) = 1, P(3) = 27, P(4) = 64 is

  • A. 8x^2 – 19x + 12
  • B. 8x^2 + 19x + 12
  • C. -8x^2 – 19x + 12
  • D. -8x^2 – 19x - 12

Answer: A. 8x^2 – 19x + 12

Explanation: For P(x) = 8x² − 19x + 12: P(1) = 8 − 19 + 12 = 1, P(3) = 72 − 57 + 12 = 27, and P(4) = 128 − 76 + 12 = 64. Matches all conditions.

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