A certain population of ALOHA users manages to generate 70 request/sec. If the time is slotted in units of 50 msec, then channel load would be
- A. 4.25
- B. 450
- C. 3.5
- D. 350
Answer: C. 3.5
Explanation: G = Rate * Time = 70 * 0.05 = 3.5.
All ISRO Computer Science (CSE) papers | ISRO Computer Science (CSE) 2015
A certain population of ALOHA users manages to generate 70 request/sec. If the time is slotted in units of 50 msec, then channel load would be
Answer: C. 3.5
Explanation: G = Rate * Time = 70 * 0.05 = 3.5.
Previous question | Next question | All questions of ISRO Computer Science (CSE) 2015