In a class B subnet, we know the IP address of one host and the mask as given below: IP address: 125.134.112.66 Mask: 255.255.224.0. What is the first address (Network address)?
- A. 125.134.96.0
- B. 125.134.112.0
- C. 125.134.112.66
- D. 125.134.0.0
Answer: A. 125.134.96.0
Explanation: 112 (01110000) AND 224 (11100000) = 01100000 (96).