If the frame buffer has 8 bits per pixel and 8 bits are allocated for each of the R, G, B components, what would be the size of the lookup table?
- A. 24 bytes
- B. 1024 bytes
- C. 768 bytes
- D. 256 bytes
Answer: C. 768 bytes
Explanation: 8 bits per pixel means $2^8 = 256$ entries in the LUT. Each entry maps to R, G, B (8 bits each = 3 bytes). Total size = $256 \times 3 = 768$ bytes.