If the pdf of a Poisson distribution is given by f(x) = e^-2 2^x / x! then its mean is
- A. 2^x
- B. 2
- C. -2
- D. 1
Answer: B. 2
Explanation: For Poisson, mean = lambda. Here lambda = 2.
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If the pdf of a Poisson distribution is given by f(x) = e^-2 2^x / x! then its mean is
Answer: B. 2
Explanation: For Poisson, mean = lambda. Here lambda = 2.
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