The table below gives values of a function F(x) obtained for values of x at intervals of 0.25. [Table: x: 0, 0.25, 0.5, 0.75, 1.0; F(x): 1, 0.9412, 0.8, 0.64, 0.50] The value of the integral of the function between the limits 0 to 1 using Simpson's rule is
- A. 0.7854
- B. 2.3562
- C. 3.1416
- D. 7.5000