Operations Research - ISRO Mechanical & Aerospace Subject-Wise PYQ Practice
Practice topic-wise Operations Research previous year questions for ISRO Mechanical & Aerospace with instant step-by-step solutions and formula breakdowns.
All ISRO Mechanical & Aerospace papers
11 questions.
Question 1
Year: 2008 | Topic: Industrial Engineering
The following data pertain to a worker: base rate = Rs. 20 per hour, Time taken for completing the job = 2 hours, Standard time = 3 hours. Under Halsey plan the total earning of the worker is
- A. Rs. 36.67
- B. Rs. 40.67
- C. Rs. 46.67
- D. Rs. 56.57
Answer: C. Rs. 46.67
Explanation: Under the Halsey plan, E = R*Ta + (Time saved / Standard time) * R * (Ts - Ta). Here time saved = 3 - 2 = 1 hr. E = (20 * 2) + (1/3) * 20 * (3 - 2) = 40 + 6.67 = 46.67 Rs.
Question 2
Year: 2017 | Topic: Industrial Engineering
A statistical process control chart which shows the number of defects found in a subgroup of fixed size is
- A. C-chart
- B. R-chart
- C. Control chart
- D. Gantt chart
Answer: A. C-chart
Explanation: A C-chart is an attributes control chart used for monitoring the number of defects per unit when the sample size is fixed.
Question 3
Year: 2017 | Topic: Industrial Engineering
In process charts, the symbol used for inspection is
- A. A circle
- B. A square
- C. An arrow
- D. A triangle
Answer: B. A square
Explanation: In process flow charts, a square symbol represents an inspection step, where an object is checked for its quality or quantity.
Question 4
Year: 2017 | Topic: Industrial Engineering
Transportation method is concerned with
- A. Value analysis
- B. Linear programming
- C. Queuing theory
- D. Break-even analysis
Answer: B. Linear programming
Explanation: The transportation problem is a classic application of linear programming, used to find the most efficient routes to transport goods from sources to destinations.
Question 5
Year: 2017 | Topic: Industrial Engineering
In dynamic balancing of machines, which of the following is NOT a method of measuring the magnitude and location of correction weight for a two plane correction?
- A. Pivoted cradle method
- B. Mechanical compensation method
- C. Pivoted compensation method
- D. Nodal point method
Answer: C. Pivoted compensation method
Explanation: Pivoted compensation method is not a standard recognized method for dynamic balancing. The other three are established techniques.
Question 6
Year: 2017 | Topic: Industrial Engineering
Adaptive response rate forecasting is related to
- A. Production Planning
- B. Production Scheduling
- C. Value analysis
- D. Inventory control
Answer: D. Inventory control
Explanation: Adaptive response rate forecasting is a technique for estimating demand in inventory control systems, particularly for items with changing demand patterns.
Question 7
Year: 2017 | Topic: Industrial Engineering
Fredric W Taylor introduced a system of working known as
- A. line organization
- B. effective organization
- C. functional organization
- D. none of the above
Answer: C. functional organization
Explanation: F.W. Taylor, the father of scientific management, advocated for functional organization, where workers receive orders from several different specialist supervisors, each with expertise in a specific area.
Question 8
Year: 2018 | Topic: Industrial Engineering
PERT has following time estimate
- A. one time estimate
- B. two time estimate
- C. three time estimate
- D. nil time estimate
Answer: C. three time estimate
Explanation: PERT uses three time estimates: Optimistic time estimate, Pessimistic time estimate, and Most likely time estimate.
Question 9
Year: 2024 | Topic: Industrial Engineering
A manufacturer has the following data regarding a product. Fixed cost per month = Rs.80,000, Variable cost per unit = Rs.350, Selling price per unit = Rs.500, Production capacity = 1600 units per month. If the production is carried out at 75% of the rated capacity, then monthly profit is (in Rs.)
- A. 1 Lakh
- B. 1.2 Lakhs
- C. 1.4 Lakhs
- D. 0.8 Lakhs
Answer: A. 1 Lakh
Explanation: Actual units produced = $0.75 * 1600 = 1200$ units. Total revenue = $1200 * 500 = 6,00,000$ Rs. Total cost = Fixed Cost + (Variable Cost * Units) = $80,000 + (350 * 1200) = 80,000 + 4,20,000 = 5,00,000$ Rs. Monthly profit = Total Revenue - Total Cost = $6,00,000 - 5,00,000 = 1,00,000$ Rs (1 Lakh).
Question 10
Year: 2024 | Topic: Industrial Engineering
For a PERT activity, the optimistic time is 6 minutes, the most likely time is 9 minutes and pessimistic time is 16 minutes. The expected time of the activity (in seconds) is
Answer: D. 580
Explanation: Expected time $T_e = (t_o + 4t_m + t_p) / 6 = (6 + 4(9) + 16) / 6 = (6 + 36 + 16) / 6 = 58 / 6$ minutes. Converting to seconds: $(58 / 6) * 60 = 58 * 10 = 580$ seconds.
Question 11
Year: 2024 | Topic: Industrial Engineering
For a particular project, six activities are to be carried out. The precedence relation and duration of activities are as per the following table. The minimum project completion time (in days) is (A=6, B follows A=5, C follows A=8, D follows B=11, E follows C=6, F follows D,E=7)
Answer: C. 29
Explanation: There are two paths to completion in the network network: Path 1 is A -> B -> D -> F which takes 6 + 5 + 11 + 7 = 29 days. Path 2 is A -> C -> E -> F which takes 6 + 8 + 6 + 7 = 27 days. The minimum project completion time is dictated by the critical (longest) path, which is 29 days.