Topic: Signals and Systems
Laplace transform of $e^{θt} \sin(ωt)$ is:
- A. θ / (S² + ω^2)
- B. ω / ((S - θ)^2 + ω^2)
- C. θ / (S² - (θ - ω)^2)
- D. θ / ((S + θ)^2 - ω^2)
Answer: B. ω / ((S - θ)^2 + ω^2)
Explanation: L[sin ωt] = ω / (s² + ω^2). Using frequency shifting property, L[e^(θt) sin ωt] = ω / ((s - θ)^2 + ω^2).