Topic: Analog Electronics
A BJT is having common emitter current gain 100. Considering 10 V supply and V_BE = 0.7 V what will be the value of R_C and R_B to set the quiescent point at I_C = 10 mA and V_CE = 8 V?
- A. R_C = 200 Ή, R_B = 93 kΉ
- B. R_C = 2 kΉ, R_B = 100 kΉ
- C. R_B = 83 kΉ, R_C = 100 Ή
- D. R_C = 20 Ή, R_B = 93 kΉ
Answer: A. R_C = 200 Ή, R_B = 93 kΉ
Explanation: R_C = (V_CC - V_CE) / I_C = (10 - 8) / 10 mA = 0.2 kΉ = 200 Ή. I_B = I_C / Β = 10 mA / 100 = 0.1 mA. R_B = (V_CC - V_BE) / I_B = (10 - 0.7) / 0.1 mA = 93 kΉ.