ISRO Electronics & Communication (ECE) 2015 - Question 21

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Topic: Communications

The noise figure of a device is 2. If input SNR is 37 dB, what would be output SNR?

  • A. 18.5 dB
  • B. 34 dB
  • C. 40 dB
  • D. 74 dB

Answer: B. 34 dB

Explanation: Noise figure = 2. Noise figure (in dB) = 10 log_10 (2) = 3 dB. Noise figure (NF) = (S/N)_input / (S/N)_output. ∴ NF (in dB) = (S/N)_input,dB - (S/N)_output,dB. So, (S/N)_output,dB = 37 - 3 = 34 dB.

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